ODBC 函数
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odbc_data_source

(PHP 4 >= 4.3.0, PHP 5)

odbc_data_source — Returns information about a current connection

说明

array odbc_data_source ( resource $connection_id , int $fetch_type )

This function will return the list of available DSN (after calling it several times).

参数

connection_id

ODBC 连接标识符，详见 odbc_connect()。

fetch_type

The fetch_type can be one of two constant types: SQL_FETCH_FIRST, SQL_FETCH_NEXT. Use SQL_FETCH_FIRST the first time this function is called, thereafter use the SQL_FETCH_NEXT.

返回值

Returns FALSE on error, and an array upon success.

ODBC 函数
在线手册：中文 英文
PHP手册
PHP手册 - N: Returns information about a current connection

用户评论:

critmas at hotmail dot com (25-Feb-2005 07:53)

Thank you Angelo for point out the code.  Though the function doesn't really do what it is supposed to.  It returns the entire list of ODBC DSNs.
If you really are looking to get the server type based on just the ODBC, username and password in an environment where the application needs to be aware of different types of databases, use the following code:

$link2 = odbc_connect($dsn , $DBUser, $DBPwd ) or die(odbc_errormsg() );
$result = @odbc_data_source( $link2, SQL_FETCH_FIRST );
while($result)
{
    if (strtolower($dsn) == strtolower($result['server'])) {
        echo $result['description'] . "<br>\n";
        break;
    }
       else
        $result = @odbc_data_source( $link2, SQL_FETCH_NEXT );
}

odbc_close($link2);

// Hope it saves your precious time

angelo [at] spaceblue [dot] com (01-Dec-2003 06:51)

// Example usage:

// Connect to a ODBC database that exists on your system
$link = odbc_connect("some_dsn_name", "user", "password") or die(odbc_errormsg() );

$result = @odbc_data_source( $link, SQL_FETCH_FIRST );
while($result)
{
    echo "DSN: " . $result['server'] . " - " . $result['description'] . "<br>\n";
    $result = @odbc_data_source( $link, SQL_FETCH_NEXT );
}

odbc_close($link);