Calendar 函数
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unixtojd

(PHP 4, PHP 5)

unixtojd — 转变Unix时间戳为Julian Day计数

说明

int unixtojd ([ int $timestamp = time() ] )

根据指定的Unix时间戳timestamp，返回Julian天数。如果没有指定时间戳则返回当前日期的天数。

参数

timestamp

一个用于转变的时间戳。

返回值

一个julian天数。

参见

Calendar 函数
在线手册：中文 英文
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PHP手册 - N: 转变Unix时间戳为Julian Day计数

用户评论:

Anonymous (21-Mar-2012 05:01)

Since upgrading from PHP 5.2.9 to 5.3.10, PHP is throwing the error:

... PHP Fatal error:  Call to undefined function unixtojd() in .../unixtojd.php on line 5

Checking phpinfo(), I can see that the calendar lib is enabled:
'--enable-calendar=shared'

Searching on Google for posts since the first release of PHP 5.3 (June 30, 2009) did not reveal much more: http://goo.gl/2YbWj

If anyone has an answer, please notify me at lsiden at gmail since I have not found a way to get notified here.

Thank you!

hrabi at linuxwaves dot com (29-Mar-2007 02:02)

according to http://www.decimaltime.hynes.net/dates.html#jd and reading "X. Calendar Functions" on this side, it seems that php "jd" is precisely mean as "Chronological Julian Day" (should it be named cjd, and primarily strictly mentioned - isn't it?), used for covnersion between calendar systems. Than it's ok (but Incomplete manual is strongly confusing here IMHO).
Even that, cJD is adjusted to a local time, so... I am rather babeled now, so nothing else :-).

hrabi at linuxwaves dot com (29-Mar-2007 11:33)

This is unusable. Julian Day start at noon, not midnight. It's better to use Fabio solution (however there is a lurk problem with leap second).

<?php
function mmd($txt, $str_time) {
   $t = strtotime($str_time);
   $j = unixtojd($t);
   $s = gmstrftime('%D %T %Z', $t);
   $j_fabio = $t / 86400 + 2440587.5;

   printf("${txt} => (%s) %s, %s U, %s J, or %s J<br>\n", $str_time, $s, $t, $j, $j_fabio);
}

//$xt = strtotime("1.1.1970 15:00.00 GMT");
$sam = "9.10.1995 02:00.01 GMT";
$spm = "9.10.1995 22:00.01 GMT";

// unixtojd for $spm returns 2450000 (OK), but for $sam returns 2450000 too! (it is wrong).
mmd("am", $sam);  // should be 2449999 (+ 0.58334)
mmd("pm", $spm);  // should be 2450000 (+ 0.41668)
?>

reference
unix time, and UTC, TAI, ntp, ... problems: http://en.wikipedia.org/wiki/Unix_time
Julian Date Converter: http://aa.usno.navy.mil/data/docs/JulianDate.html
history overview: http://parris.josh.com.au/humour/work/17Nov1858.shtml

fabio at llgp dot org (31-Aug-2006 10:09)

If you need an easy way to convert an unix timestamp to a decimal julian day you can use:

$julianDay = $unixTimeStamp / 86400 + 2440587.5;

86400 is the number of seconds in a day;
2440587.5 is the julian day at 1/1/1970 0:00 UTC.

(11-Aug-2006 03:22)

Its clearly stated that this function returns the Julian Day, not Julian Day + time.

If you want the time with it you will have to do something like:

$t=time();
$jd=unixtojd($t)+($t%60*60*24)/60*60*24;

johnston at capsaicin dot ca (19-Nov-2003 09:43)

Also note that epoch is in UTC time (epoch is a specific point in time - epoch is not different for every time zone), so be aware of timezone complexities.

pipian at pipian dot com (12-Jun-2003 05:29)

Remember that UNIX timestamps indicate a number of seconds from midnight of January 1, 1970 on the Gregorian calendar, not the Julian Calendar.